Fibonacci series: Any number in the series is obtained by adding
the previous two numbers of the series.
Let f(n) be n'th term.
f(0)=0;
f(1)=1;
f(n)=f(n-1)+f(n-2); (for n>=2)
Series is as follows
011
(1+0)
2 (1+1)
3 (1+2)
5 (2+3)
8 (3+5)
13 (5+8)
21 (8+13)
34 (13+21)
...and so on
Program: to generate Fibonacci Series(10 terms)
#include<stdio.h>
int main() {
//array fib stores numbers of fibonacci series
int i, fib[25];
//initialized first element to 0
fib[0] = 0;
//initialized second element to 1
fib[1] = 1;
//loop to generate ten elements
for (i = 2; i < 10; i++) {
//i'th element of series is equal to the sum of i-1'th element and
i-2'th element.
fib[i] = fib[i - 1] + fib[i - 2];
}
printf("The fibonacci series is as follows \n");
//print all numbers in the series
for (i = 0; i < 10; i++) {
printf("%d \n", fib[i]);
}
return 0;
}
Output:
The fibonacci series is as follows
01123581
3
21
34
Explanation:
The first two elements are initialized to 0, 1 respectively. Other
elements in the series are generated by looping
and adding previous two numbes. These numbers are stored in an array and
ten elements of the series are
printed as output.
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This page was last modified on 15 Dec 2011 at 19:41:59. |
Gautam Kumar EDP Manager  http://www.connectsin.com |
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